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Gen Chemistry 1: Module 4 Chemical Reactions

.MODULE TITLE - CHEMICAL REACTIONS

 

This module is especially made for Grade 11 STEM students to enjoy learning General Chemistry 1 hassle-free and effectively at home. This module provides is based on the competency/ies from the Most Essential Learning Competencies (MELC) developed by the Department of Education as a part of the Learning Continuity Plan (LCP).

 

OVERVIEW:

Topics to be discussed in this module:

· Writing and balancing chemical equations

· Types of Reactions

· Stoichiometry: mole-to-mole relationships;

· Stoichiometry: grams-to-mole-to-mole-to-grams relationships;

· Limiting Reactant and Reaction Yields

 

MOST ESSENTIAL LEARNING COMPETENCIES:

At the end of this module, you should be able to answer the following questions:

1.       How do you balance a chemical equation?

2.       What are the indications of a chemical change?

3.       What are the types of chemical reactions?

4.       How are limiting and excess reagents determined in a chemical reaction?

 

 


 

Chemical Reaction

When a substance undergoes changes in its composition, a chemical change or chemical reaction occurs. In a chemical reaction, one or more reactants change into one or more products, and this is represented by chemical equations. Chemical equations are symbolic representations of chemical processes that use standardized notation to communicate information in an efficient manner. These equations follow the general form:

 

Reactants    Products

 

where the reactants are written on the left and products on the right. The reactants and the products are separated by an arrow, which indicates some change occurs as a result of the process. The arrow is read as yields, gives, or reacts to produce.

 

Evidences for Chemical Reactions

1. Change in color;

2. Formation of solid products (precipitates);

3. Release of gas; 

4.  Change in temperature; and

5.  Production of flame.

 

Examples:

1. Smooth and shiny steel becomes reddish-brown and flaky when it rusts;

2. A colored dress discolored when bleached;

3. Blue flame is produced when natural gas burns;

4. CO2 gas fizzes when vinegar is poured on eggshells;

5. Milk curdles when you add lime juice;

6. White precipitates are formed when aqueous solutions of NaCl and AgNO3 are mixed

 

Writing Chemical Equations

Chemical reactions are represented by chemical equations.

Chemical reactions involve the re-grouping of atoms in molecules or compounds.  For example, when methane gas (CH4) reacts with oxygen gas, atoms in CH4 and O2          molecules break up and then recombine to form H2O and CO2. This reaction is             conveniently represented by a chemical equation. For example,

Word equation:  Methane gas + oxygen gas  → carbon dioxide gas + water vapor

Chemical equation:   CH4(g)  +  2 O2(g)       CO2(g)                  + H2O(g)

 

Exercise-1: Write the unbalanced chemical equation for each of the following reactions:

1.  Magnesium reacts with oxygen gas to form solid magnesium oxide.

 

 

2.  Calcium metal reacts with water to form calcium hydroxide precipitate and hydrogen gas.

 

 

3.  Solid ammonium carbonate decomposes when heated to produce solid ammonia gas, carbon dioxide gas, and water vapor.

 

 

4.  Nitrogen reacts with hydrogen to form ammonia gas.

 

 

 

Balancing Chemical Equations

                According to the law of conservation of mass, atoms are neither created nor      destroyed in chemical reactions.  Therefore, a chemical equation should have equal numbers of each type of atoms on both reactant and product sides. We say that the equation is balanced.

               

Example:

Not balanced:     C3H8(g)  +  O2(g)     CO2(g)  +  H2O(g)

                                (3C, 8H, 2O)               (1C, 2H, 3O) 

 

Balanced eqn.:   C3H8(g)  +  5 O2(g)     3CO2(g)  +  4H2O(g)

                                  (3C, 8H, 10 O)                    (3C, 8H, 10 O)

 

How to write and balance equations?

1. All reactants and products of a reaction must be known before attempting to write an equation.

2. Identify the reactants and products and write their chemical symbols or formulas CORRECTLY.  

3. Indicate the state of substances: (g) for gas, (l) for liquid, (s) for solid, and (aq) for aqueous solution.

4. Balance the equation by introducing smallest integer (whole number) coefficients in front of each reactant and product as needed, (coefficient "1" is not shown). The chemical formula of any substances MUST NOT be changed. For example, the formula for sodium chloride is NaCl; it CANNOT be written as Na2Cl2 or any other forms.

 

Finally, inspect the equation – check that each type of atoms (or group of atoms) is equal on both sides of the equation.

Balancing Process: the following steps may be used to make balancing easier:

1.  Balance first elements that occur in only one compound on each side of the equation;

2.  Balance last elements that occur in more than one compound.

 

Rules in Balancing Equations:

· NEVER CHANGE the chemical formula of any of the substances (reactants or products);

· NEVER introduce extra formulas that are not parts of the reaction.

 

Examples:

1.  Hydrogen and oxygen gases react to form liquid water.  Write the chemical equation.

      Unbalanced equation:               H2(g)    +  O2(g)    H2O(l);

      Balanced equation:                    2 H2(g) +  O2(g)    2 H2O(l)

      Inspection:                                         ( 4H, 2O)            (4H, 2O) 

 

2.  Propane gas (C3H8) burns in air (reacts with oxygen) to form carbon dioxide gas and water vapor.  Write a balanced chemical equation for the reaction

 

      Unbalanced equation:               C3H8(g)  +    O2(g)     CO2(g)    +  H2O(g)

      Balanced equation:                    C3H8(g)  +  5 O2(g)    3CO2(g)  +  4H2O(g)

Inspection:                                       (3C, 8H, 10O)               (3 C, 8H, 10O)

 

 

Balanced chemical equations provide the following information:

· The identity of reactants and products; and

· The molar relationships between one substance to another represented in the               equation.

 

 

Exercise-2:

A.        Write a balanced equation for each of the following reactions:

1.        Solid ammonium nitrite decomposes to form nitrogen gas and water vapor.

 

 

 

 

 

2.        Baking powder (sodium hydrogen carbonate) decomposes to produce solid sodium carbonate, carbon dioxide gas, and water vapor.

 

 

 

 

 

3.        Solid calcium carbonate reacts with aqueous hydrochloric acid solution to yield aqueous calcium chloride solution and carbon dioxide gas.

 

 

 

 

 

4.        Solid ammonium dichromate, (NH4)2Cr2O7(s), readily decomposes to produce solid chromium(III) oxide, nitrogen gas, and gaseous water.

 

 

 

 

 

B.        Balance the following equation using smallest whole number coefficients:

 

1.        ___C4H10O(l)  +  ___O2(g)    ___CO2(g)  +  ___H2O(g)

 

2.        ___Al2O3(s)  +  ___HCl(aq)     ___AlCl3(aq)  +  ___H2O(l)

 

3.        ___PCl5(s)  +  ___H2O(l)     ___H3PO4(aq)  +  ___HCl(aq)

 

4.        ___H3PO4(aq) + ___NaOH(aq)     ___H2O(l) + ___Na3PO4(aq)

 

5.        ___NH3(g)  +  ___O2(g)     ___NO(g)  +  ___H2O(g)

 

6.        ___Ba(OH)2(aq) + ___H3PO4(aq)     ___H2O(l)  +  ___Ba3(PO4)2(s) 

 

7.        ___Mg3N2(s)  + ___H2O(l)    ___Mg(OH)2(s)  +  ___NH3(g)

Classification of Reactions

Oxidation-Reduction or Redox Reactions - these are reactions that involve the transfer of electrons.

· Oxidation  è lost of electrons;

· Reduction  è gain of electrons;

· Oxidizing agent  è the reactant that gains electrons;

· Reducing agent  è the reactant that loses electrons;

 

Types of Redox Reactions:

1. Combination Reactions:

(a)  Reaction between sodium metal and chlorine gas:  2 Na(s)  +  Cl2(g)    2 NaCl(s)

(1)  Oxidation half-reaction - lost of electrons:  2 Na  → 2 Na+ + 2e-;

(2)  Reduction half-reaction - gain of electrons:   Cl2 + 2e-  → 2Cl-;

————–———-———————————————————————————

Oxidation-reduction reaction:          2 Na(s) + Cl2(g)     2 Na+ + 2 Cl- → 2NaCl(s)

———————————————————————————————————

                                                    Net:        2 Na(s) + Cl2(g)     2 NaCl(s)

                                                    ———————————————————————-

In the above reaction, sodium loses an electron and is oxidized to Na+, while chlorine gains an electron and is reduced to Cl-.  In this reaction, sodium is the reducing agent and chlorine the oxidizing agent.

 

 

(b)  Reaction of magnesium with oxygen:  2Mg(s) +  O2(g)     2MgO(s);

(1)  Oxidation half-reaction - lost of electrons:  2Mg  → Mg2+ + 4e-;

(2)  Reduction half-reaction - gain of electrons:  O2 +  4e-  → 2 O2-;

————————————————–——————————————————

Oxidation-reduction reaction:  2Mg(s) +  O2(g)    2Mg2+ + 2 O2-    2MgO(s)

————————————————————–——————————————

                                                                  Net:           2Mg(s) +  O2(g)     2MgO(s)

                                                                  —————————–-——————————

In the above reaction, Mg is the reducing agent and it is oxidized to Mg2+, while oxygen is the oxidizing agent and it is reduced to O2-.

 

 

(c) Reaction of aluminum metal with chlorine gas:  2Al(s)  +  3Cl2(g)    2AlCl3(s)

(1)  Oxidation half-reaction - lost of electrons:  2Al    2Al3+ +  6e-;

(2)  Reduction half-reaction - gain of electrons:  3Cl2 +  6e-    6Cl-;

————————————————————————–——————————

Oxidation-reduction reaction: 2Al(s)  +  3Cl2(g)    2Al3+ +  6Cl-  2AlCl3(s)

————————————————————————————–——————

                                                  Net:  2Al(s)  +  3Cl2(g)    2AlCl3(s)

                                                  ———————————————————–———--

(d)  Reaction between aluminum and sulfur: 2 Al(s) + 3 S(s)  → Al2S3(s)

(1)  Oxidation half-reaction - lost of electrons:  2 Al  → 2 Al3+  + 6 e-;

(2)  Reduction half-reaction - gain of electrons:  3 S + 6e-  → 3 S2-;

 

Exercise-3:

For each reaction below, show how electrons are lost and gained by the elements         involved?

1.        2 K(s) + Br2(l)    2KBr(s);                                      3.     Ca(s)  +  F2(g)    CaF2(s);

2.    2 Cu(s) + S(s)    Cu2S(s);                                           4.     6 Na(s)  +  N2(g)     2Na3N(s)

 

__________________________________________________________________________________

 

Other types of Redox Reactions:

2. Decomposition Reactions

A reaction in which a compound breaks up into two or more elements or simpler          compounds.

Examples:  (1)    2 KClO3(s)  → 2 KCl(s)  +  3 O2(g)

                      (2)    (NH4)2Cr2O7(s)  → Cr2O3(s)  +  N2(g)  +  4 H2O(g)

                      (3)    2 HgO(s)    2 Hg(l) + O2(g);

 

 

3.  Single Replacement Reactions

This is a redox reaction in which an element in a compound is replaced by another      element.

Examples:   (1)  Zn(s)  +  2HCl(aq)    ZnCl2(aq)  +  H2(g);                        (Zn replaces H)

                       (2)  Mg(s)  +  CuSO4(aq)    MgSO4(aq) +  Cu(s);                (Mg replaces Cu)

                       (3)  Cl2(aq) +  2KI(aq)     2KCl(aq)  +  I2(aq) ;                         (Cl replaces I)

 

4.  Combustion Reactions

These are reactions with molecular oxygen (oxygen gas), which are always accompanied by the release of a large amount of heat and flame.

 

Examples:   (1)  CH4(g)  +  2 O2(g)  → CO2(g)  +  2H2O(g)

                        (2)  C3H8(g)  +  5 O2(g)  → 3CO2(g)  +  4H2O(g)

                        (3)   2C4H10(g)  +  13 O2(g)  → 8CO2(g)  +  10H2O(g)

                        (4)   2C8H18(l)  +  25 O2(g)   → 16CO2(g)  +  18H2O(g)

                        (5)   C(s)  +  O2(g)   → CO2(g)                 

__________________________________________________________________________________

 

Examples of combination and decomposition reactions which are NOT redox reactions:

1.  CaO(s) + SO2(g)    CaSO3(s);                  4.  LiOH(aq) +  CO2(g)    LiHCO3(aq)

2. CaCO3(s)    CaO(s)  +  CO2(g);                 5. Mg(OH)2(s)    MgO(s) +  H2O(g)

3. 2NaHCO3(s)  → Na2CO3(s) + H2O(g) + CO2(g)

 

__________________________________________________________________________________

 

Exercise-4 :  Classify each of the following reactions, first as redox or nonredox. Then further classify as combination, decomposition, single replacement, or combustion:

 

1.            Fe2O3(s) + 2 Al(s)    Al2O3(s) + 2 Fe(s)                                        _______________________________________________

2.            3 Mg(s) + N2(g)    Mg3N2(s)                                                                    _______________________________________________

3.            4 NH3(g) + 5 O2(g)  → 4 NO(g) + 6 H2O(g)                                  _______________________________________________

5.            4 HNO3(aq)  → 2 H2O(g) + 4 NO2(g) + O2(g)                             _______________________________________________

6.            C2H5OH(l) + 3 O2(g)  → 2 CO2(g) + 3 H2O(l)  _______________________________________________

7.            SO3(g)  +  H2O(l)     H2SO4(aq)                                                            _______________________________________________

8.            (NH4)2CO3(s)    CO2(g) + 2NH3(g) + H2O(l)                        _______________________________________________

__________________________________________________________________________________

Other Types of Reactions

 

Double-Displacement Reactions

These are reactions in aqueous solution that involve the exchange of ions between the reacting species of the type:

 

                                AB + CD  → AD + CB

 

The two types of double-displacement reactions are precipitation and neutralization or acid-base reactions.

 

A. Precipitation reactions are reactions that result in the formation of precipitates (solid products) because at least one of the products of the reaction is not soluble in water.

For example,

 

                1.  Pb(NO3)2(aq)  +  K2C rO4(aq)  → PbCrO4(s)  +  2 KNO3(aq)

                2.  AgNO3(aq)  +  KBr(aq)   → AgBr(s) +  KNO3(aq)

                3.  BaCl2(aq) +  Na2SO4(aq)    BaSO4(s)  +  2NaCl(aq)

 

The products, PbCrO4, AgBr, and BaSO4 are only slightly soluble or insoluble in water.

 

B. Acid-base (or Neutralization) reactions are reactions in aqueous solution that form salts and water as the products. Examples:

 

                1.  HCl(aq)  +  NaOH(aq)    NaCl(aq)  +  H2O(l)

                2.  H2SO4(aq)  +  2 KOH(aq)    K2SO4(aq)  +  2 H2O(l)

                3.  HC2H3O2(aq)  +  NaOH(aq)    NaC2H3O2(aq)  +  H2O(l)

 

Some double-displacement reactions may result in both the formation of precipitates and water.  They can be classified as both precipitation and acid-base reactions.

For examples:

 

                1.  Ba(OH)2(aq)  +  H2SO4(aq)   → BaSO4(s) +  2 H2O(l)

                2.  3Ca(OH)2(aq)  +  2H3PO4(aq)    Ca3(PO4)2(s)  +  6 H2O(l)

Information obtained from Chemical Equations

A chemical equation tells us what type of chemical changes take place during a chemical reaction. While a balanced chemical equation also tells the molar relationships between one reactant to another, and between reactants and products. Consider the following balanced chemical equation:

 

                CO(g)  +  2H2(g)  → CH3OH(l)

 

Mole-to-Mole Relationships

The coefficients in balanced equation give mole relationships between reactants and products.  Since mole quantity is directly related to mass, the equation also provide information regarding mass relationships between substances involved in the reaction. For example, the above equation implies that:

 

One CO molecule reacts with two H2 molecules to form one CH3OH molecule.

Or,          one mole of CO reacts with two moles of H2 to form one mole of CH3OH.

 

The stoichiometric ratios in the above reaction are:  1 mol CH3OH  and  1 mol CH3OH

                                                                                                                1 mol CO                     2 mol H2

These mole ratios can serve as conversion factors in stoichiometric calculations.

 

 

 

The combustion reaction of propane gas, C3H8(g), represented by the following equation,

                                C3H8(g)  +  5 O2(g)     3 CO2(g)  +  4 H2O(g)

 

implies that one mole of C3H8 reacts with 5 moles of O2 to yield 3 moles of CO2 and 4 moles of H2O.

 

Exercise-5:

1. For the combustion of propane gas according to the following reaction:

 

                                C3H8(g)  +  5 O2(g)    3 CO2(g)  +  4 H2O(g);

 

(a) How many moles of oxygen gas will react with one mole of propane?

(b) How many moles of CO2 and H2O, respectively, are formed from one mole of propane reacted?

(c) How many mole moles of O2 gas are required to react exactly with 0.25 mol of C3H8? 

(d) How many moles of C3H8 are combusted if 3.75 moles of O2 were consumed during the reaction?.

(e) How many moles of CO2 and H2O, respectively, will be produced from the       complete combustion of  0.25 mole of propane gas? 

 

2.        Ammonia is produced by the following reaction:  N2(g)  +  3 H2(g)    2 NH3(g)

(a) How many moles of ammonia are produced if 12.0 moles of H2 are completely reacted?

(b) How many moles nitrogen gas are needed to react completely with 12.0 moles of hydrogen gas according to the above reaction?

(c) How many moles each of N2 and H2, respectively, are needed to produce 12.0 moles of ammonia according to the above equation?

 

__________________________________________________________________________________

 

Calculations of Masses

 

Mass-to-Mole-to-Mole-to-Mass Relationships

                In any given reaction, if the mass of one of the reactants is given, its quantity in moles can be obtained. Then the moles of the other reactant or the product can be        determined from the balanced equation. This quantity in moles of the other reactant or product(s) can be converted back to their respective masses.

 

Consider the formation of CH3OH from CO and H2 according to the equation:

                                CO(g)  +  2 H2(g)    CH3OH(l)

 

Suppose that the reaction uses 454 g of CO gas, how many grams of hydrogen gas are also reacted, and how many grams of methanol, CH3OH, are formed?

 

Solution:  First we have to convert 454 g of CO to moles of CO gas:

                ? Moles of CO = 454 g x    1 mol CO    =  16.2 mol CO;

                                                                   28.01 g CO

 

 

 

Using the balanced equation, we find how many moles and grams of H2 that will react with 454 g of CO:

                ? Moles of H2 = 16.2 mol CO x   2 mol H2   = 32.4 mol H2;

                                                                             1 mol CO

                ? grams of H2 = 32.4 mol H2 x  2.016 g H2  = 65.3 g H2

                                                                             1 mol H2

 

Next, we calculate the moles and grams of methanol that would be formed if the reaction occurs to completion. That is, all of CO are reacted.

 

                ? Moles of CH3OH = 16.2 mol CO x  1 mol CH3OH   =  16.2 mol CH3OH

                                                                                           1 mol CO

                ? Grams of CH3OH = 16.2 mol CH3OH  x   32.04 g CH3OH  =  519 g CH3OH

                                                                                                     1 mol CH3OH

Exercise-6: 

1.        In the following reaction to produce ammonia:  N2(g)  +  3H2(g)    2NH3(g)

            (a) How many grams of H2 gas are needed to react completely with 454 g of          nitrogen gas?  (b) How many grams of ammonia will be formed if 454 g of N2(g) are completely reacted?  (c) How many grams of N2 and H2, respectively, are needed to produce 907 g of ammonia?

 

2.        What mass of oxygen gas is required to react completely with 680. g of octane, C8H18, in the following reaction:

                                2 C8H18(l)  +  25 O2(g)   → 16 CO2(g)  +  18 H2O(g)

 

3.        Baking soda, NaHCO3, and milk of magnesia, which is an aqueous suspension of magnesium hydroxide, Mg(OH)2(s), are used as antacids.  Both neutralize excess hydrochloric acid secreted by the stomach.  (a) Write a balanced equation for the reaction: (i) between NaHCO3(s) and HCl(aq); (ii) between Mg(OH)2 and HCl(aq). 

(b) How many moles of HCl(aq) will be reacted by: (i) 10.0 g of NaHCO3; (ii) 10.0 g of Mg(OH)2 ? Which is the more effective antacid, NaHCO3 or Mg(OH)2? 

 

__________________________________________________________________________________

 

Reactions Involving Limiting Reactant

When reactants are mixed in stoichiometric quantities, all reactants will be    completely consumed at the same time.  At the end of the reaction, only products but none of the reactants exist.  For example, in the reaction,

                                CH4(g)  +  H2O(g)    CO(g)  +  3 H2(g)

 

if exactly 16 g of CH4 and 18 g of steam, (or in other quantity of similar proportion), are allowed to react completely, there will not be any reactants remains at the end of the   reaction. The products are 28 g of CO and 6 g of H2 (or other quantities of similar         proportions).

On the other hand, if 16 g of CH4 are mixed with 25 g of steam and allowed to react    completely, all of CH4 and only 18 g of steam will be completely reacted, but 7 g of steam will remain in excess.  We say that CH4 is a limiting reagent because it gets used up    before steam.  The products of this reaction are 28 g CO and 6 g H2. The yield of products formed is determined by the amount of limiting reactant that is reacted.

 

Steps for solving stoichiometric problems involving limiting reactants

1. Write a balanced equation for the reaction

2. Convert given masses, in grams, of reactants into moles.

3. Compare the mole ratio of available reactants to the stoichiometric mole ratio        according to the balanced equation. Then determine which reactant is the limiting reagent.

4. Alternatively, you may calculate the theoretical yield of the product based on the available amount of each reactant. The one that gives the lower product yield is the limiting reactant.

Exercise-7:

1.        In the following reaction to produce ammonia: N2(g)  +  3 H2(g)    2 NH3(g)

(a) if 91.3 g of nitrogen gas and 18.0 g of hydrogen gas are mixed, which is the    limiting reactant?

(b) How many grams of ammonia are formed when the limiting reactant is           completely reacted. 

 

2.        In a thermite reaction, 31.9 g of iron(III) oxide, Fe2O3, is reacted with 12.0 g of aluminum.  (a) Which is the limiting reagent?  (b) How many grams of iron are formed in this reaction?

 

                                2 Al(s)  +  Fe2O3(s)    Al2O3(s)  +  2 Fe(s)

__________________________________________________________________________________

 

Theoretical Yield, Actual Yield, and Percent Yield

      Theoretical yield = the expected amount products formed based on the amount of limiting reactant.

· Actual yield = actual amount of product obtained in an experiment;

· Percent Yield =  (Actual Yield/Theoretical Yield)  x  100%

 

Exercise-8:

1.        685 g of CO(g) is reacted with excess of H2(g) according to the following equation:

                                2 H2(g)  +  CO(g)    CH3OH(l)

 

            (a) Assuming that the reaction goes to completion, calculate the theoretical yield of methanol.  (b)  If 357 g of CH3OH is actually obtained, what is the percent yield of methanol in this reaction?

 

 

2.        Silicon (Si) is prepared from silicon tetrachloride, SiCl4, by reaction with magnesium metal according to the following equation:

 

                                2 Mg(s)  +  SiCl4(l)    2 MgCl2(s)  +  Si(s)

 

            (a)  How many grams of silicon are expected when 454 g of SiCl4 are reacted with an excess of magnesium?  (b)  If only 60.5 g of silicon are actually obtained, what is the percent yield of silicon from this reaction?

 

__________________________________________________________________________________

REFERENCES:

Ilao, L., Lontoc, B., & Gayon, E. E. (2016). General Chemistry 1. Quezon City, Ph: Rex Bookstore, Inc. 

Kim, A. (2020, 5 31). Clipartkey. Retrieved from clipartley.com/view/Ttibwnjk

 

 

 

 


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